What are the solutions to the equation x^2-16x=20 ?

The solutions to the equation x^2-16x=20 are x=2(4+sqrt(21)),x=2(4-sqrt(21))

Find the zeros of x^2-16x=20

The zeros of x^2-16x=20 are x=2(4+sqrt(21)),x=2(4-sqrt(21))

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x^{2} - 16 x = 20

x = 2 (4 + 21), x = 2 (4 - 21)

Solution steps

x^{2} - 16 x = 20

Move

20

to the left side

x^{2} - 16 x - 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 \cdot 1 \cdot ( - 20 )}{2 \cdot 1}

(- 16)^{2} - 4 \cdot 1 \cdot (- 20) = 421

x_{1, 2} = \frac{- ( - 16 ) \pm 4 21}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 16 ) + 4 21}{2 \cdot 1}, x_{2} = \frac{- ( - 16 ) - 4 21}{2 \cdot 1}

x = \frac{- ( - 16 ) + 4 21}{2 \cdot 1} : 2 (4 + 21)

x = \frac{- ( - 16 ) - 4 21}{2 \cdot 1} : 2 (4 - 21)

The solutions to the quadratic equation are:

x = 2 (4 + 21), x = 2 (4 - 21)

x, x^{2} + 4 y^{2} - 4 x + 6 y + 20 = 0

X, Y = 2 X^{2}

- 16 x^{2} = - 25

7 x + 3 x^{2} - 8 = - 1

32 - 18 m^{2} = 0

What are the solutions to the equation x^2-16x=20 ?
The solutions to the equation x^2-16x=20 are x=2(4+sqrt(21)),x=2(4-sqrt(21))
Find the zeros of x^2-16x=20
The zeros of x^2-16x=20 are x=2(4+sqrt(21)),x=2(4-sqrt(21))