What are the solutions to the equation -16x^2=-25 ?

The solutions to the equation -16x^2=-25 are x= 5/4 ,x=-5/4

Find the zeros of -16x^2=-25

The zeros of -16x^2=-25 are x= 5/4 ,x=-5/4

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- 16 x^{2} = - 25

x = \frac{5}{4}, x = - \frac{5}{4}

Solution steps

- 16 x^{2} = - 25

Divide both sides by

- 16

x^{2} = \frac{25}{16}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{25}{16}, x = - \frac{25}{16}

\frac{25}{16} = \frac{5}{4}

- \frac{25}{16} = - \frac{5}{4}

x = \frac{5}{4}, x = - \frac{5}{4}

7 x + 3 x^{2} - 8 = - 1

32 - 18 m^{2} = 0

6 a^{2} + 5 a - 6 = 0

x^{2} + 20 x - 17 = 7

(w - 3)^{2} = 29 - 5 w

What are the solutions to the equation -16x^2=-25 ?
The solutions to the equation -16x^2=-25 are x= 5/4 ,x=-5/4
Find the zeros of -16x^2=-25
The zeros of -16x^2=-25 are x= 5/4 ,x=-5/4