What are the solutions to the equation 7x+3x^2-8=-1 ?

The solutions to the equation 7x+3x^2-8=-1 are x=(-7+sqrt(133))/6 ,x=(-7-sqrt(133))/6

Find the zeros of 7x+3x^2-8=-1

The zeros of 7x+3x^2-8=-1 are x=(-7+sqrt(133))/6 ,x=(-7-sqrt(133))/6

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7 x + 3 x^{2} - 8 = - 1

x = \frac{- 7 + 133}{6}, x = \frac{- 7 - 133}{6}

Solution steps

7 x + 3 x^{2} - 8 = - 1

Move

1

to the left side

3 x^{2} + 7 x - 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 3 ( - 7 )}{2 \cdot 3}

7^{2} - 4 \cdot 3 (- 7) = 133

x_{1, 2} = \frac{- 7 \pm 133}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 7 + 133}{2 \cdot 3}, x_{2} = \frac{- 7 - 133}{2 \cdot 3}

x = \frac{- 7 + 133}{2 \cdot 3} : \frac{- 7 + 133}{6}

x = \frac{- 7 - 133}{2 \cdot 3} : \frac{- 7 - 133}{6}

The solutions to the quadratic equation are:

x = \frac{- 7 + 133}{6}, x = \frac{- 7 - 133}{6}

32 - 18 m^{2} = 0

6 a^{2} + 5 a - 6 = 0

x^{2} + 20 x - 17 = 7

(w - 3)^{2} = 29 - 5 w

- x^{2} - 14 x + 21 = - 2 x + 7

What are the solutions to the equation 7x+3x^2-8=-1 ?
The solutions to the equation 7x+3x^2-8=-1 are x=(-7+sqrt(133))/6 ,x=(-7-sqrt(133))/6
Find the zeros of 7x+3x^2-8=-1
The zeros of 7x+3x^2-8=-1 are x=(-7+sqrt(133))/6 ,x=(-7-sqrt(133))/6