What are the solutions to the equation x^2+20x-17=7 ?

The solutions to the equation x^2+20x-17=7 are x=2(sqrt(31)-5),x=-2(5+sqrt(31))

Find the zeros of x^2+20x-17=7

The zeros of x^2+20x-17=7 are x=2(sqrt(31)-5),x=-2(5+sqrt(31))

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x^{2} + 20 x - 17 = 7

x = 2 (31 - 5), x = - 2 (5 + 31)

Solution steps

x^{2} + 20 x - 17 = 7

Move

7

to the left side

x^{2} + 20 x - 24 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 1 \cdot ( - 24 )}{2 \cdot 1}

2 0^{2} - 4 \cdot 1 \cdot (- 24) = 431

x_{1, 2} = \frac{- 20 \pm 4 31}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 20 + 4 31}{2 \cdot 1}, x_{2} = \frac{- 20 - 4 31}{2 \cdot 1}

x = \frac{- 20 + 4 31}{2 \cdot 1} : 2 (31 - 5)

x = \frac{- 20 - 4 31}{2 \cdot 1} : - 2 (5 + 31)

The solutions to the quadratic equation are:

x = 2 (31 - 5), x = - 2 (5 + 31)

(w - 3)^{2} = 29 - 5 w

- x^{2} - 14 x + 21 = - 2 x + 7

(3 x + 4)^{2} = 0

x, (x + y)^{2} y = 9

x^{2} + 2 = 3 x^{2} - 16

What are the solutions to the equation x^2+20x-17=7 ?
The solutions to the equation x^2+20x-17=7 are x=2(sqrt(31)-5),x=-2(5+sqrt(31))
Find the zeros of x^2+20x-17=7
The zeros of x^2+20x-17=7 are x=2(sqrt(31)-5),x=-2(5+sqrt(31))