What are the solutions to the equation -x^2+16x+0=0 ?

The solutions to the equation -x^2+16x+0=0 are x=0,x=16

Find the zeros of -x^2+16x+0=0

The zeros of -x^2+16x+0=0 are x=0,x=16

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- x^{2} + 16 x + 0 = 0

x = 0, x = 16

Solution steps

- x^{2} + 16 x + 0 = 0

Refine

- x^{2} + 16 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 ( - 1 ) \cdot 0}{2 ( - 1 )}

1 6^{2} - 4 (- 1) \cdot 0 = 16

x_{1, 2} = \frac{- 16 \pm 16}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 16 + 16}{2 ( - 1 )}, x_{2} = \frac{- 16 - 16}{2 ( - 1 )}

x = \frac{- 16 + 16}{2 ( - 1 )} : 0

x = \frac{- 16 - 16}{2 ( - 1 )} : 16

The solutions to the quadratic equation are:

x = 0, x = 16

(x - a)^{2} + x^{2} = 2 a^{2}

4 x^{2} + x - 14 = 0

- 3 x^{2} + 9 x + 5

6 a^{2} + 2 a - 113 = - 9

x \frac{4 x - 3}{5} - \frac{2 x - 3}{2} = - 2

What are the solutions to the equation -x^2+16x+0=0 ?
The solutions to the equation -x^2+16x+0=0 are x=0,x=16
Find the zeros of -x^2+16x+0=0
The zeros of -x^2+16x+0=0 are x=0,x=16