What are the solutions to the equation 8x^2+22x+12=0 ?

The solutions to the equation 8x^2+22x+12=0 are x=-3/4 ,x=-2

Find the zeros of 8x^2+22x+12=0

The zeros of 8x^2+22x+12=0 are x=-3/4 ,x=-2

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8 x^{2} + 22 x + 12 = 0

x = - \frac{3}{4}, x = - 2

Decimal Notation

x = - 0.75, x = - 2

Solution steps

8 x^{2} + 22 x + 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 22 \pm 2 2 ^{2} - 4 \cdot 8 \cdot 12}{2 \cdot 8}

2 2^{2} - 4 \cdot 8 \cdot 12 = 10

x_{1, 2} = \frac{- 22 \pm 10}{2 \cdot 8}

Separate the solutions

x_{1} = \frac{- 22 + 10}{2 \cdot 8}, x_{2} = \frac{- 22 - 10}{2 \cdot 8}

x = \frac{- 22 + 10}{2 \cdot 8} : - \frac{3}{4}

x = \frac{- 22 - 10}{2 \cdot 8} : - 2

The solutions to the quadratic equation are:

x = - \frac{3}{4}, x = - 2

- 3 x^{2} + 4 x + 59 = - 8 x - 4

(x - 5) (40 - x) = 4 (40 - x)

2 x + x^{2} = 4

x^{2} - 12 x + 36

x, x^{2} + y^{2} - 6 x - 6 y + 18 = 0

What are the solutions to the equation 8x^2+22x+12=0 ?
The solutions to the equation 8x^2+22x+12=0 are x=-3/4 ,x=-2
Find the zeros of 8x^2+22x+12=0
The zeros of 8x^2+22x+12=0 are x=-3/4 ,x=-2