What are the solutions to the equation 4x^2+16x+4=0 ?

The solutions to the equation 4x^2+16x+4=0 are x=-2+sqrt(3),x=-2-sqrt(3)

Find the zeros of 4x^2+16x+4=0

The zeros of 4x^2+16x+4=0 are x=-2+sqrt(3),x=-2-sqrt(3)

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4 x^{2} + 16 x + 4 = 0

x = - 2 + 3, x = - 2 - 3

Solution steps

4 x^{2} + 16 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 \cdot 4 \cdot 4}{2 \cdot 4}

1 6^{2} - 4 \cdot 4 \cdot 4 = 83

x_{1, 2} = \frac{- 16 \pm 8 3}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 16 + 8 3}{2 \cdot 4}, x_{2} = \frac{- 16 - 8 3}{2 \cdot 4}

x = \frac{- 16 + 8 3}{2 \cdot 4} : - 2 + 3

x = \frac{- 16 - 8 3}{2 \cdot 4} : - 2 - 3

The solutions to the quadratic equation are:

x = - 2 + 3, x = - 2 - 3

(x + 6) (x + 3) = 4

3 p^{2} + 5 p = 68

n^{2} - 4 n + 3 = 0

2 x + 2 = x^{2} + 4 x + 3

2 x^{2} + 16 x - 20 = 0

What are the solutions to the equation 4x^2+16x+4=0 ?
The solutions to the equation 4x^2+16x+4=0 are x=-2+sqrt(3),x=-2-sqrt(3)
Find the zeros of 4x^2+16x+4=0
The zeros of 4x^2+16x+4=0 are x=-2+sqrt(3),x=-2-sqrt(3)