What are the solutions to the equation 2x^2+13x+18=0 ?

The solutions to the equation 2x^2+13x+18=0 are x=-2,x=-9/2

Find the zeros of 2x^2+13x+18=0

The zeros of 2x^2+13x+18=0 are x=-2,x=-9/2

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2 x^{2} + 13 x + 18 = 0

x = - 2, x = - \frac{9}{2}

Decimal Notation

x = - 2, x = - 4.5

Solution steps

2 x^{2} + 13 x + 18 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 13 \pm 1 3 ^{2} - 4 \cdot 2 \cdot 18}{2 \cdot 2}

1 3^{2} - 4 \cdot 2 \cdot 18 = 5

x_{1, 2} = \frac{- 13 \pm 5}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 13 + 5}{2 \cdot 2}, x_{2} = \frac{- 13 - 5}{2 \cdot 2}

x = \frac{- 13 + 5}{2 \cdot 2} : - 2

x = \frac{- 13 - 5}{2 \cdot 2} : - \frac{9}{2}

The solutions to the quadratic equation are:

x = - 2, x = - \frac{9}{2}

x^{2} - 3 + 2 x = 0

2 x^{2} - 3 x (20) + 50 (20)^{2} = 28000

y, x^{3} - 2 x^{2} y + 3 x y^{2} = 38

2 4^{2} + b^{2} = 2 6^{2}

r, v = πh r^{2}

What are the solutions to the equation 2x^2+13x+18=0 ?
The solutions to the equation 2x^2+13x+18=0 are x=-2,x=-9/2
Find the zeros of 2x^2+13x+18=0
The zeros of 2x^2+13x+18=0 are x=-2,x=-9/2