What are the solutions to the equation 3x^2-2x-17=-1 ?

The solutions to the equation 3x^2-2x-17=-1 are x= 8/3 ,x=-2

Find the zeros of 3x^2-2x-17=-1

The zeros of 3x^2-2x-17=-1 are x= 8/3 ,x=-2

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3 x^{2} - 2 x - 17 = - 1

x = \frac{8}{3}, x = - 2

Solution steps

3 x^{2} - 2 x - 17 = - 1

Move

1

to the left side

3 x^{2} - 2 x - 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 3 ( - 16 )}{2 \cdot 3}

(- 2)^{2} - 4 \cdot 3 (- 16) = 14

x_{1, 2} = \frac{- ( - 2 ) \pm 14}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 14}{2 \cdot 3}, x_{2} = \frac{- ( - 2 ) - 14}{2 \cdot 3}

x = \frac{- ( - 2 ) + 14}{2 \cdot 3} : \frac{8}{3}

x = \frac{- ( - 2 ) - 14}{2 \cdot 3} : - 2

The solutions to the quadratic equation are:

x = \frac{8}{3}, x = - 2

(z - 6)^{2} = 2 z

5 x^{2} + 13 x - 46 = 0

x^{2} + b x = 0

p^{2} - 14 p + 44 = - 2

0 = x^{(2)} + 2 x - 15

What are the solutions to the equation 3x^2-2x-17=-1 ?
The solutions to the equation 3x^2-2x-17=-1 are x= 8/3 ,x=-2
Find the zeros of 3x^2-2x-17=-1
The zeros of 3x^2-2x-17=-1 are x= 8/3 ,x=-2