What are the solutions to the equation 5x^2+13x-46=0 ?

The solutions to the equation 5x^2+13x-46=0 are x=2,x=-23/5

Find the zeros of 5x^2+13x-46=0

The zeros of 5x^2+13x-46=0 are x=2,x=-23/5

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5 x^{2} + 13 x - 46 = 0

x = 2, x = - \frac{23}{5}

Solution steps

5 x^{2} + 13 x - 46 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 13 \pm 1 3 ^{2} - 4 \cdot 5 ( - 46 )}{2 \cdot 5}

1 3^{2} - 4 \cdot 5 (- 46) = 33

x_{1, 2} = \frac{- 13 \pm 33}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 13 + 33}{2 \cdot 5}, x_{2} = \frac{- 13 - 33}{2 \cdot 5}

x = \frac{- 13 + 33}{2 \cdot 5} : 2

x = \frac{- 13 - 33}{2 \cdot 5} : - \frac{23}{5}

The solutions to the quadratic equation are:

x = 2, x = - \frac{23}{5}

x^{2} + b x = 0

p^{2} - 14 p + 44 = - 2

0 = x^{(2)} + 2 x - 15

x, z^{2} = x^{2} + x y^{2} z

4 w^{2} + 25 = - 20 w

What are the solutions to the equation 5x^2+13x-46=0 ?
The solutions to the equation 5x^2+13x-46=0 are x=2,x=-23/5
Find the zeros of 5x^2+13x-46=0
The zeros of 5x^2+13x-46=0 are x=2,x=-23/5