What are the solutions to the equation p^2-14p+44=-2 ?

The solutions to the equation p^2-14p+44=-2 are p=7+sqrt(3),p=7-sqrt(3)

Find the zeros of p^2-14p+44=-2

The zeros of p^2-14p+44=-2 are p=7+sqrt(3),p=7-sqrt(3)

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p^{2} - 14 p + 44 = - 2

p = 7 + 3, p = 7 - 3

Solution steps

p^{2} - 14 p + 44 = - 2

Move

2

to the left side

p^{2} - 14 p + 46 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 \cdot 1 \cdot 46}{2 \cdot 1}

(- 14)^{2} - 4 \cdot 1 \cdot 46 = 23

p_{1, 2} = \frac{- ( - 14 ) \pm 2 3}{2 \cdot 1}

Separate the solutions

p_{1} = \frac{- ( - 14 ) + 2 3}{2 \cdot 1}, p_{2} = \frac{- ( - 14 ) - 2 3}{2 \cdot 1}

p = \frac{- ( - 14 ) + 2 3}{2 \cdot 1} : 7 + 3

p = \frac{- ( - 14 ) - 2 3}{2 \cdot 1} : 7 - 3

The solutions to the quadratic equation are:

p = 7 + 3, p = 7 - 3

0 = x^{(2)} + 2 x - 15

x, z^{2} = x^{2} + x y^{2} z

4 w^{2} + 25 = - 20 w

0 = 3 x^{2} + 10 x - 8

(x + 5)^{2} = - 16

What are the solutions to the equation p^2-14p+44=-2 ?
The solutions to the equation p^2-14p+44=-2 are p=7+sqrt(3),p=7-sqrt(3)
Find the zeros of p^2-14p+44=-2
The zeros of p^2-14p+44=-2 are p=7+sqrt(3),p=7-sqrt(3)