What are the solutions to the equation 5+81x^2=21 ?

The solutions to the equation 5+81x^2=21 are x= 4/9 ,x=-4/9

Find the zeros of 5+81x^2=21

The zeros of 5+81x^2=21 are x= 4/9 ,x=-4/9

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5 + 81 x^{2} = 21

x = \frac{4}{9}, x = - \frac{4}{9}

Decimal Notation

x = 0.44444 \dots, x = - 0.44444 \dots

Solution steps

5 + 81 x^{2} = 21

Move

5

to the right side

81 x^{2} = 16

Divide both sides by

81

x^{2} = \frac{16}{81}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{16}{81}, x = - \frac{16}{81}

\frac{16}{81} = \frac{4}{9}

- \frac{16}{81} = - \frac{4}{9}

x = \frac{4}{9}, x = - \frac{4}{9}

5 x^{2} + 4 x + 9 = 0

2 x^{2} - x = - 8

(7 - 3 x) (x + 2) = 4

x^{2} - 6 x - 7 = 0

15000 = - 0.5 x^{2} + 40 x - 300

What are the solutions to the equation 5+81x^2=21 ?
The solutions to the equation 5+81x^2=21 are x= 4/9 ,x=-4/9
Find the zeros of 5+81x^2=21
The zeros of 5+81x^2=21 are x= 4/9 ,x=-4/9