What are the solutions to the equation 2x+6x^2=16 ?

The solutions to the equation 2x+6x^2=16 are x=(-1+sqrt(97))/6 ,x=-(1+sqrt(97))/6

Find the zeros of 2x+6x^2=16

The zeros of 2x+6x^2=16 are x=(-1+sqrt(97))/6 ,x=-(1+sqrt(97))/6

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2 x + 6 x^{2} = 16

x = \frac{- 1 + 97}{6}, x = - \frac{1 + 97}{6}

Decimal Notation

x = 1.47480 \dots, x = - 1.80814 \dots

Solution steps

2 x + 6 x^{2} = 16

Move

16

to the left side

2 x + 6 x^{2} - 16 = 0

Write in the standard form

a x^{2} + b x + c = 0

6 x^{2} + 2 x - 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 6 ( - 16 )}{2 \cdot 6}

2^{2} - 4 \cdot 6 (- 16) = 297

x_{1, 2} = \frac{- 2 \pm 2 97}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 2 + 2 97}{2 \cdot 6}, x_{2} = \frac{- 2 - 2 97}{2 \cdot 6}

x = \frac{- 2 + 2 97}{2 \cdot 6} : \frac{- 1 + 97}{6}

x = \frac{- 2 - 2 97}{2 \cdot 6} : - \frac{1 + 97}{6}

The solutions to the quadratic equation are:

x = \frac{- 1 + 97}{6}, x = - \frac{1 + 97}{6}

x, x^{2} + 2 a x + a^{2} - n = 0

x^{2} + 2 x + 65 = 0

x^{2} - 10 x = - 11

x^{2} - 10 x = - 13

x^{2} - 10 x = - 15

What are the solutions to the equation 2x+6x^2=16 ?
The solutions to the equation 2x+6x^2=16 are x=(-1+sqrt(97))/6 ,x=-(1+sqrt(97))/6
Find the zeros of 2x+6x^2=16
The zeros of 2x+6x^2=16 are x=(-1+sqrt(97))/6 ,x=-(1+sqrt(97))/6