What are the solutions to the equation -2x^2-4x+7=0 ?

The solutions to the equation -2x^2-4x+7=0 are x=-(2+3sqrt(2))/2 ,x=(3sqrt(2)-2)/2

Find the zeros of -2x^2-4x+7=0

The zeros of -2x^2-4x+7=0 are x=-(2+3sqrt(2))/2 ,x=(3sqrt(2)-2)/2

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- 2 x^{2} - 4 x + 7 = 0

x = - \frac{2 + 3 2}{2}, x = \frac{3 2 - 2}{2}

Decimal Notation

x = - 3.12132 \dots, x = 1.12132 \dots

Solution steps

- 2 x^{2} - 4 x + 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 ( - 2 ) \cdot 7}{2 ( - 2 )}

(- 4)^{2} - 4 (- 2) \cdot 7 = 62

x_{1, 2} = \frac{- ( - 4 ) \pm 6 2}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 6 2}{2 ( - 2 )}, x_{2} = \frac{- ( - 4 ) - 6 2}{2 ( - 2 )}

x = \frac{- ( - 4 ) + 6 2}{2 ( - 2 )} : - \frac{2 + 3 2}{2}

x = \frac{- ( - 4 ) - 6 2}{2 ( - 2 )} : \frac{3 2 - 2}{2}

The solutions to the quadratic equation are:

x = - \frac{2 + 3 2}{2}, x = \frac{3 2 - 2}{2}

(x + 2) (4 x - 3) = 0

4 n^{2} - 8 n - 12 = 0

x, 4 x^{2} - 16 x = 0

3 x^{2} - 9 x - 6 = 0

11 x^{2} + 18 x - 7 = 0

What are the solutions to the equation -2x^2-4x+7=0 ?
The solutions to the equation -2x^2-4x+7=0 are x=-(2+3sqrt(2))/2 ,x=(3sqrt(2)-2)/2
Find the zeros of -2x^2-4x+7=0
The zeros of -2x^2-4x+7=0 are x=-(2+3sqrt(2))/2 ,x=(3sqrt(2)-2)/2