What are the solutions to the equation (x+2)(4x-3)=0 ?

The solutions to the equation (x+2)(4x-3)=0 are x=-2,x= 3/4

Find the zeros of (x+2)(4x-3)=0

The zeros of (x+2)(4x-3)=0 are x=-2,x= 3/4

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(x + 2) (4 x - 3) = 0

x = - 2, x = \frac{3}{4}

Decimal Notation

x = - 2, x = 0.75

Solution steps

(x + 2) (4 x - 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 2 = 0 or 4 x - 3 = 0

Solve

x + 2 = 0 : x = - 2

Solve

4 x - 3 = 0 : x = \frac{3}{4}

The solutions to the quadratic equation are:

x = - 2, x = \frac{3}{4}

4 n^{2} - 8 n - 12 = 0

x, 4 x^{2} - 16 x = 0

3 x^{2} - 9 x - 6 = 0

11 x^{2} + 18 x - 7 = 0

- x^{2} - 3 x + 7 = 0

What are the solutions to the equation (x+2)(4x-3)=0 ?
The solutions to the equation (x+2)(4x-3)=0 are x=-2,x= 3/4
Find the zeros of (x+2)(4x-3)=0
The zeros of (x+2)(4x-3)=0 are x=-2,x= 3/4