What are the solutions to the equation 11x^2+18x-7=0 ?

The solutions to the equation 11x^2+18x-7=0 are x=(-9+sqrt(158))/(11),x=-(9+sqrt(158))/(11)

Find the zeros of 11x^2+18x-7=0

The zeros of 11x^2+18x-7=0 are x=(-9+sqrt(158))/(11),x=-(9+sqrt(158))/(11)

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11 x^{2} + 18 x - 7 = 0

x = \frac{- 9 + 158}{11}, x = - \frac{9 + 158}{11}

Decimal Notation

x = 0.32452 \dots, x = - 1.96089 \dots

Solution steps

11 x^{2} + 18 x - 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 18 \pm 1 8 ^{2} - 4 \cdot 11 ( - 7 )}{2 \cdot 11}

1 8^{2} - 4 \cdot 11 (- 7) = 2158

x_{1, 2} = \frac{- 18 \pm 2 158}{2 \cdot 11}

Separate the solutions

x_{1} = \frac{- 18 + 2 158}{2 \cdot 11}, x_{2} = \frac{- 18 - 2 158}{2 \cdot 11}

x = \frac{- 18 + 2 158}{2 \cdot 11} : \frac{- 9 + 158}{11}

x = \frac{- 18 - 2 158}{2 \cdot 11} : - \frac{9 + 158}{11}

The solutions to the quadratic equation are:

x = \frac{- 9 + 158}{11}, x = - \frac{9 + 158}{11}

- x^{2} - 3 x + 7 = 0

x, - x^{2} + 3 x + 40 = 0

0 = - 16 t^{2} + 96 t + 112

4 x^{2} + 16 x - 5 = 0

x^{2} - 16 x + 17 = 0

What are the solutions to the equation 11x^2+18x-7=0 ?
The solutions to the equation 11x^2+18x-7=0 are x=(-9+sqrt(158))/(11),x=-(9+sqrt(158))/(11)
Find the zeros of 11x^2+18x-7=0
The zeros of 11x^2+18x-7=0 are x=(-9+sqrt(158))/(11),x=-(9+sqrt(158))/(11)