What are the solutions to the equation -x^2-3x+7=0 ?

The solutions to the equation -x^2-3x+7=0 are x=-(3+sqrt(37))/2 ,x=(sqrt(37)-3)/2

Find the zeros of -x^2-3x+7=0

The zeros of -x^2-3x+7=0 are x=-(3+sqrt(37))/2 ,x=(sqrt(37)-3)/2

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- x^{2} - 3 x + 7 = 0

x = - \frac{3 + 37}{2}, x = \frac{37 - 3}{2}

Decimal Notation

x = - 4.54138 \dots, x = 1.54138 \dots

Solution steps

- x^{2} - 3 x + 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 ( - 1 ) \cdot 7}{2 ( - 1 )}

(- 3)^{2} - 4 (- 1) \cdot 7 = 37

x_{1, 2} = \frac{- ( - 3 ) \pm 37}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 37}{2 ( - 1 )}, x_{2} = \frac{- ( - 3 ) - 37}{2 ( - 1 )}

x = \frac{- ( - 3 ) + 37}{2 ( - 1 )} : - \frac{3 + 37}{2}

x = \frac{- ( - 3 ) - 37}{2 ( - 1 )} : \frac{37 - 3}{2}

The solutions to the quadratic equation are:

x = - \frac{3 + 37}{2}, x = \frac{37 - 3}{2}

x, - x^{2} + 3 x + 40 = 0

0 = - 16 t^{2} + 96 t + 112

4 x^{2} + 16 x - 5 = 0

x^{2} - 16 x + 17 = 0

x^{2} + 5 x - 21 = 0

What are the solutions to the equation -x^2-3x+7=0 ?
The solutions to the equation -x^2-3x+7=0 are x=-(3+sqrt(37))/2 ,x=(sqrt(37)-3)/2
Find the zeros of -x^2-3x+7=0
The zeros of -x^2-3x+7=0 are x=-(3+sqrt(37))/2 ,x=(sqrt(37)-3)/2