What are the solutions to the equation 0=-16t^2+96t+112 ?

The solutions to the equation 0=-16t^2+96t+112 are t=-1,t=7

Find the zeros of 0=-16t^2+96t+112

The zeros of 0=-16t^2+96t+112 are t=-1,t=7

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0 = - 16 t^{2} + 96 t + 112

t = - 1, t = 7

Solution steps

0 = - 16 t^{2} + 96 t + 112

Switch sides

- 16 t^{2} + 96 t + 112 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 96 \pm 9 6 ^{2} - 4 ( - 16 ) \cdot 112}{2 ( - 16 )}

9 6^{2} - 4 (- 16) \cdot 112 = 128

t_{1, 2} = \frac{- 96 \pm 128}{2 ( - 16 )}

Separate the solutions

t_{1} = \frac{- 96 + 128}{2 ( - 16 )}, t_{2} = \frac{- 96 - 128}{2 ( - 16 )}

t = \frac{- 96 + 128}{2 ( - 16 )} : - 1

t = \frac{- 96 - 128}{2 ( - 16 )} : 7

The solutions to the quadratic equation are:

t = - 1, t = 7

4 x^{2} + 16 x - 5 = 0

x^{2} - 16 x + 17 = 0

x^{2} + 5 x - 21 = 0

x, 2088.4 x^{2} - 15070 x + 5697.2 = 0

(x - 3)^{2} = - 8 (x + 1)

What are the solutions to the equation 0=-16t^2+96t+112 ?
The solutions to the equation 0=-16t^2+96t+112 are t=-1,t=7
Find the zeros of 0=-16t^2+96t+112
The zeros of 0=-16t^2+96t+112 are t=-1,t=7