What are the solutions to the equation 5x(1-x)=x ?

The solutions to the equation 5x(1-x)=x are x=0,x= 4/5

Find the zeros of 5x(1-x)=x

The zeros of 5x(1-x)=x are x=0,x= 4/5

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5 x (1 - x) = x

x = 0, x = \frac{4}{5}

Decimal Notation

x = 0, x = 0.8

Solution steps

5 x (1 - x) = x

Expand

5 x (1 - x) : 5 x - 5 x^{2}

5 x - 5 x^{2} = x

Move

x

to the left side

- 5 x^{2} + 4 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 ( - 5 ) \cdot 0}{2 ( - 5 )}

4^{2} - 4 (- 5) \cdot 0 = 4

x_{1, 2} = \frac{- 4 \pm 4}{2 ( - 5 )}

Separate the solutions

x_{1} = \frac{- 4 + 4}{2 ( - 5 )}, x_{2} = \frac{- 4 - 4}{2 ( - 5 )}

x = \frac{- 4 + 4}{2 ( - 5 )} : 0

x = \frac{- 4 - 4}{2 ( - 5 )} : \frac{4}{5}

The solutions to the quadratic equation are:

x = 0, x = \frac{4}{5}

k^{2} = k

x^{2} + 4 x + 3 = 3

x^{2} - 8 x = - 6 x - 6 x

\frac{9}{4} x^{2} - 16 = 0

0.2 x^{2} - 0.9 x + 1 = 0

What are the solutions to the equation 5x(1-x)=x ?
The solutions to the equation 5x(1-x)=x are x=0,x= 4/5
Find the zeros of 5x(1-x)=x
The zeros of 5x(1-x)=x are x=0,x= 4/5