What are the solutions to the equation 3t^2-9t-7=5 ?

The solutions to the equation 3t^2-9t-7=5 are t=4,t=-1

Find the zeros of 3t^2-9t-7=5

The zeros of 3t^2-9t-7=5 are t=4,t=-1

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3 t^{2} - 9 t - 7 = 5

t = 4, t = - 1

Solution steps

3 t^{2} - 9 t - 7 = 5

Move

5

to the left side

3 t^{2} - 9 t - 12 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 3 ( - 12 )}{2 \cdot 3}

(- 9)^{2} - 4 \cdot 3 (- 12) = 15

t_{1, 2} = \frac{- ( - 9 ) \pm 15}{2 \cdot 3}

Separate the solutions

t_{1} = \frac{- ( - 9 ) + 15}{2 \cdot 3}, t_{2} = \frac{- ( - 9 ) - 15}{2 \cdot 3}

t = \frac{- ( - 9 ) + 15}{2 \cdot 3} : 4

t = \frac{- ( - 9 ) - 15}{2 \cdot 3} : - 1

The solutions to the quadratic equation are:

t = 4, t = - 1

a, a + 38 a^{2} b + a b^{2} = - 409

- 0.0083 x^{2} + 0.78 x + 23.5 = 0

- 4 x^{2} + 16 = 340

x^{2} + 8 x - 30 = 0

7 x^{2} = 4

What are the solutions to the equation 3t^2-9t-7=5 ?
The solutions to the equation 3t^2-9t-7=5 are t=4,t=-1
Find the zeros of 3t^2-9t-7=5
The zeros of 3t^2-9t-7=5 are t=4,t=-1