What are the solutions to the equation v^2+18v+81=50 ?

The solutions to the equation v^2+18v+81=50 are v=-9+5sqrt(2),v=-9-5sqrt(2)

Find the zeros of v^2+18v+81=50

The zeros of v^2+18v+81=50 are v=-9+5sqrt(2),v=-9-5sqrt(2)

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v^{2} + 18 v + 81 = 50

v = - 9 + 52, v = - 9 - 52

Decimal Notation

v = - 1.92893 \dots, v = - 16.07106 \dots

Solution steps

v^{2} + 18 v + 81 = 50

Move

50

to the left side

v^{2} + 18 v + 31 = 0

Solve with the quadratic formula

v_{1, 2} = \frac{- 18 \pm 1 8 ^{2} - 4 \cdot 1 \cdot 31}{2 \cdot 1}

1 8^{2} - 4 \cdot 1 \cdot 31 = 102

v_{1, 2} = \frac{- 18 \pm 10 2}{2 \cdot 1}

Separate the solutions

v_{1} = \frac{- 18 + 10 2}{2 \cdot 1}, v_{2} = \frac{- 18 - 10 2}{2 \cdot 1}

v = \frac{- 18 + 10 2}{2 \cdot 1} : - 9 + 52

v = \frac{- 18 - 10 2}{2 \cdot 1} : - 9 - 52

The solutions to the quadratic equation are:

v = - 9 + 52, v = - 9 - 52

4 x^{2} = 32 x - 64

x^{2} - 11 x - 105 = - 7 x^{2}

9 m^{2} + m + 6 = 0

8 x^{2} + 18 x - 5 = 0

16 x^{2} + 16 x - 5 = 0

What are the solutions to the equation v^2+18v+81=50 ?
The solutions to the equation v^2+18v+81=50 are v=-9+5sqrt(2),v=-9-5sqrt(2)
Find the zeros of v^2+18v+81=50
The zeros of v^2+18v+81=50 are v=-9+5sqrt(2),v=-9-5sqrt(2)