What are the solutions to the equation factor 16x^2+16x-5=0 ?

The solutions to the equation factor 16x^2+16x-5=0 are x= 1/4 ,x=-5/4

Find the zeros of factor 16x^2+16x-5=0

The zeros of factor 16x^2+16x-5=0 are x= 1/4 ,x=-5/4

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16 x^{2} + 16 x - 5 = 0

x = \frac{1}{4}, x = - \frac{5}{4}

Decimal Notation

x = 0.25, x = - 1.25

Solution steps

16 x^{2} + 16 x - 5 = 0

Factor

16 x^{2} + 16 x - 5 : (4 x - 1) (4 x + 5)

(4 x - 1) (4 x + 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

4 x - 1 = 0 or 4 x + 5 = 0

Solve

4 x - 1 = 0 : x = \frac{1}{4}

Solve

4 x + 5 = 0 : x = - \frac{5}{4}

The solutions to the quadratic equation are:

x = \frac{1}{4}, x = - \frac{5}{4}

4 x (5 x - 6) = 0

16 x^{2} + 6 x + 7 = 0

a^{2} - 7 a + 3 = 0

p^{2} + 7 p + 6 = 0

x^{2} - 18 x - 16 = - 1

What are the solutions to the equation factor 16x^2+16x-5=0 ?
The solutions to the equation factor 16x^2+16x-5=0 are x= 1/4 ,x=-5/4
Find the zeros of factor 16x^2+16x-5=0
The zeros of factor 16x^2+16x-5=0 are x= 1/4 ,x=-5/4