What are the solutions to the equation 4x^2=32x-64 ?

The solutions to the equation 4x^2=32x-64 are x=4

Find the zeros of 4x^2=32x-64

The zeros of 4x^2=32x-64 are x=4

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4 x^{2} = 32 x - 64

x = 4

Solution steps

4 x^{2} = 32 x - 64

Move

64

to the left side

4 x^{2} + 64 = 32 x

Move

32 x

to the left side

4 x^{2} + 64 - 32 x = 0

Write in the standard form

a x^{2} + b x + c = 0

4 x^{2} - 32 x + 64 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 32 ) \pm ( - 32 ) ^{2} - 4 \cdot 4 \cdot 64}{2 \cdot 4}

(- 32)^{2} - 4 \cdot 4 \cdot 64 = 0

x_{1, 2} = \frac{- ( - 32 ) \pm 0}{2 \cdot 4}

x = \frac{- ( - 32 )}{2 \cdot 4}

\frac{- ( - 32 )}{2 \cdot 4} = 4

x = 4

The solution to the quadratic equation is:

x = 4

x^{2} - 11 x - 105 = - 7 x^{2}

9 m^{2} + m + 6 = 0

8 x^{2} + 18 x - 5 = 0

16 x^{2} + 16 x - 5 = 0

4 x (5 x - 6) = 0

What are the solutions to the equation 4x^2=32x-64 ?
The solutions to the equation 4x^2=32x-64 are x=4
Find the zeros of 4x^2=32x-64
The zeros of 4x^2=32x-64 are x=4