What are the solutions to the equation 16x^2+6x+7=0 ?

The solutions to the equation 16x^2+6x+7=0 are x=-3/16+i(sqrt(103))/(16),x=-3/16-i(sqrt(103))/(16)

Find the zeros of 16x^2+6x+7=0

The zeros of 16x^2+6x+7=0 are x=-3/16+i(sqrt(103))/(16),x=-3/16-i(sqrt(103))/(16)

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16 x^{2} + 6 x + 7 = 0

x = - \frac{3}{16} + i \frac{103}{16}, x = - \frac{3}{16} - i \frac{103}{16}

Solution steps

16 x^{2} + 6 x + 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 16 \cdot 7}{2 \cdot 16}

Simplify

6^{2} - 4 \cdot 16 \cdot 7 : 2103 i

x_{1, 2} = \frac{- 6 \pm 2 103 i}{2 \cdot 16}

Separate the solutions

x_{1} = \frac{- 6 + 2 103 i}{2 \cdot 16}, x_{2} = \frac{- 6 - 2 103 i}{2 \cdot 16}

x = \frac{- 6 + 2 103 i}{2 \cdot 16} : - \frac{3}{16} + i \frac{103}{16}

x = \frac{- 6 - 2 103 i}{2 \cdot 16} : - \frac{3}{16} - i \frac{103}{16}

The solutions to the quadratic equation are:

x = - \frac{3}{16} + i \frac{103}{16}, x = - \frac{3}{16} - i \frac{103}{16}

a^{2} - 7 a + 3 = 0

p^{2} + 7 p + 6 = 0

x^{2} - 18 x - 16 = - 1

8 x^{2} - 3 x + 1 = 0

r, v = n r^{2} h

What are the solutions to the equation 16x^2+6x+7=0 ?
The solutions to the equation 16x^2+6x+7=0 are x=-3/16+i(sqrt(103))/(16),x=-3/16-i(sqrt(103))/(16)
Find the zeros of 16x^2+6x+7=0
The zeros of 16x^2+6x+7=0 are x=-3/16+i(sqrt(103))/(16),x=-3/16-i(sqrt(103))/(16)