What are the solutions to the equation a^2-7a+3=0 ?

The solutions to the equation a^2-7a+3=0 are a=(7+sqrt(37))/2 ,a=(7-sqrt(37))/2

Find the zeros of a^2-7a+3=0

The zeros of a^2-7a+3=0 are a=(7+sqrt(37))/2 ,a=(7-sqrt(37))/2

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a^{2} - 7 a + 3 = 0

a = \frac{7 + 37}{2}, a = \frac{7 - 37}{2}

Decimal Notation

a = 6.54138 \dots, a = 0.45861 \dots

Solution steps

a^{2} - 7 a + 3 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 1 \cdot 3}{2 \cdot 1}

(- 7)^{2} - 4 \cdot 1 \cdot 3 = 37

a_{1, 2} = \frac{- ( - 7 ) \pm 37}{2 \cdot 1}

Separate the solutions

a_{1} = \frac{- ( - 7 ) + 37}{2 \cdot 1}, a_{2} = \frac{- ( - 7 ) - 37}{2 \cdot 1}

a = \frac{- ( - 7 ) + 37}{2 \cdot 1} : \frac{7 + 37}{2}

a = \frac{- ( - 7 ) - 37}{2 \cdot 1} : \frac{7 - 37}{2}

The solutions to the quadratic equation are:

a = \frac{7 + 37}{2}, a = \frac{7 - 37}{2}

p^{2} + 7 p + 6 = 0

x^{2} - 18 x - 16 = - 1

8 x^{2} - 3 x + 1 = 0

r, v = n r^{2} h

m^{2} + 36 = 0

What are the solutions to the equation a^2-7a+3=0 ?
The solutions to the equation a^2-7a+3=0 are a=(7+sqrt(37))/2 ,a=(7-sqrt(37))/2
Find the zeros of a^2-7a+3=0
The zeros of a^2-7a+3=0 are a=(7+sqrt(37))/2 ,a=(7-sqrt(37))/2