What are the solutions to the equation 2s^2-21s+49=0 ?

The solutions to the equation 2s^2-21s+49=0 are s=7,s= 7/2

Find the zeros of 2s^2-21s+49=0

The zeros of 2s^2-21s+49=0 are s=7,s= 7/2

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2 s^{2} - 21 s + 49 = 0

s = 7, s = \frac{7}{2}

Decimal Notation

s = 7, s = 3.5

Solution steps

2 s^{2} - 21 s + 49 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- ( - 21 ) \pm ( - 21 ) ^{2} - 4 \cdot 2 \cdot 49}{2 \cdot 2}

(- 21)^{2} - 4 \cdot 2 \cdot 49 = 7

s_{1, 2} = \frac{- ( - 21 ) \pm 7}{2 \cdot 2}

Separate the solutions

s_{1} = \frac{- ( - 21 ) + 7}{2 \cdot 2}, s_{2} = \frac{- ( - 21 ) - 7}{2 \cdot 2}

s = \frac{- ( - 21 ) + 7}{2 \cdot 2} : 7

s = \frac{- ( - 21 ) - 7}{2 \cdot 2} : \frac{7}{2}

The solutions to the quadratic equation are:

s = 7, s = \frac{7}{2}

5 x^{2} - 25 x + 3 = 0

n^{2} - n - 240 = 0

z^{2} + 14 z + 45 = 0

x^{2} - 2 x

x, x^{2} + 7 x - 18 = 0

What are the solutions to the equation 2s^2-21s+49=0 ?
The solutions to the equation 2s^2-21s+49=0 are s=7,s= 7/2
Find the zeros of 2s^2-21s+49=0
The zeros of 2s^2-21s+49=0 are s=7,s= 7/2