What are the solutions to the equation 3x^2-3x+3/4 =0 ?

The solutions to the equation 3x^2-3x+3/4 =0 are x= 1/2

Find the zeros of 3x^2-3x+3/4 =0

The zeros of 3x^2-3x+3/4 =0 are x= 1/2

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3 x^{2} - 3 x + \frac{3}{4} = 0

x = \frac{1}{2}

Decimal Notation

x = 0.5

Solution steps

3 x^{2} - 3 x + \frac{3}{4} = 0

Multiply both sides by

4

12 x^{2} - 12 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 12 \cdot 3}{2 \cdot 12}

(- 12)^{2} - 4 \cdot 12 \cdot 3 = 0

x_{1, 2} = \frac{- ( - 12 ) \pm 0}{2 \cdot 12}

x = \frac{- ( - 12 )}{2 \cdot 12}

\frac{- ( - 12 )}{2 \cdot 12} = \frac{1}{2}

x = \frac{1}{2}

The solution to the quadratic equation is:

x = \frac{1}{2}

\frac{1}{3} x^{2} + \frac{1}{4} x - 3 = 0

x, x^{2} + x y + y^{2} = 25

x, x^{2} + x y + y^{2} = 36

3 (7 x - 9) - (7 x - 9)^{2} = 0

x (x - 1) + 2 x - 2 = 0

What are the solutions to the equation 3x^2-3x+3/4 =0 ?
The solutions to the equation 3x^2-3x+3/4 =0 are x= 1/2
Find the zeros of 3x^2-3x+3/4 =0
The zeros of 3x^2-3x+3/4 =0 are x= 1/2