What are the solutions to the equation (x+8)^2-9x=52 ?

The solutions to the equation (x+8)^2-9x=52 are x=-3,x=-4

Find the zeros of (x+8)^2-9x=52

The zeros of (x+8)^2-9x=52 are x=-3,x=-4

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(x + 8)^{2} - 9 x = 52

x = - 3, x = - 4

Solution steps

(x + 8)^{2} - 9 x = 52

Expand

(x + 8)^{2} - 9 x : x^{2} + 7 x + 64

x^{2} + 7 x + 64 = 52

Move

52

to the left side

x^{2} + 7 x + 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 1 \cdot 12}{2 \cdot 1}

7^{2} - 4 \cdot 1 \cdot 12 = 1

x_{1, 2} = \frac{- 7 \pm 1}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 7 + 1}{2 \cdot 1}, x_{2} = \frac{- 7 - 1}{2 \cdot 1}

x = \frac{- 7 + 1}{2 \cdot 1} : - 3

x = \frac{- 7 - 1}{2 \cdot 1} : - 4

The solutions to the quadratic equation are:

x = - 3, x = - 4

4 x^{2} - 19 x - 30 = 0

2 x^{2} + x = 22 x + 11

2 x^{2} - 5 x = 33

x, 5 x^{2} + 5 y^{2} - 9 x - 14 y + 26 = 0

s, 3 a s^{2} - a n^{2} = 0

What are the solutions to the equation (x+8)^2-9x=52 ?
The solutions to the equation (x+8)^2-9x=52 are x=-3,x=-4
Find the zeros of (x+8)^2-9x=52
The zeros of (x+8)^2-9x=52 are x=-3,x=-4