What are the solutions to the equation sqrt(1000/100)=n^2-54 ?

The solutions to the equation sqrt(1000/100)=n^2-54 are n=sqrt(\sqrt{10)+54},n=-sqrt(\sqrt{10)+54}

Find the zeros of sqrt(1000/100)=n^2-54

The zeros of sqrt(1000/100)=n^2-54 are n=sqrt(\sqrt{10)+54},n=-sqrt(\sqrt{10)+54}

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\frac{1000}{100} = n^{2} - 54

n = 10 + 54, n = - 10 + 54

Decimal Notation

n = 7.56057 \dots, n = - 7.56057 \dots

Solution steps

\frac{1000}{100} = n^{2} - 54

Expand

\frac{1000}{100} : 10

10 = n^{2} - 54

Switch sides

n^{2} - 54 = 10

Move

54

to the right side

n^{2} = 10 + 54

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

n = 10 + 54, n = - 10 + 54

x^{2} - 3 x = x + 1

3 y^{2} + 12 y + 12 = 0

x^{2} + 4 x + 7

6 + x^{2} = 15

- 2 x^{2} + 4 x + 9 = 11

What are the solutions to the equation sqrt(1000/100)=n^2-54 ?
The solutions to the equation sqrt(1000/100)=n^2-54 are n=sqrt(\sqrt{10)+54},n=-sqrt(\sqrt{10)+54}
Find the zeros of sqrt(1000/100)=n^2-54
The zeros of sqrt(1000/100)=n^2-54 are n=sqrt(\sqrt{10)+54},n=-sqrt(\sqrt{10)+54}