What are the solutions to the equation x^2-3x=x+1 ?

The solutions to the equation x^2-3x=x+1 are x=2+sqrt(5),x=2-sqrt(5)

Find the zeros of x^2-3x=x+1

The zeros of x^2-3x=x+1 are x=2+sqrt(5),x=2-sqrt(5)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} - 3 x = x + 1

x = 2 + 5, x = 2 - 5

Decimal Notation

x = 4.23606 \dots, x = - 0.23606 \dots

Solution steps

x^{2} - 3 x = x + 1

Move

1

to the left side

x^{2} - 3 x - 1 = x

Move

x

to the left side

x^{2} - 4 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot ( - 1 )}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot (- 1) = 25

x_{1, 2} = \frac{- ( - 4 ) \pm 2 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 2 5}{2 \cdot 1}, x_{2} = \frac{- ( - 4 ) - 2 5}{2 \cdot 1}

x = \frac{- ( - 4 ) + 2 5}{2 \cdot 1} : 2 + 5

x = \frac{- ( - 4 ) - 2 5}{2 \cdot 1} : 2 - 5

The solutions to the quadratic equation are:

x = 2 + 5, x = 2 - 5

3 y^{2} + 12 y + 12 = 0

x^{2} + 4 x + 7

6 + x^{2} = 15

- 2 x^{2} + 4 x + 9 = 11

x^{2} + 5 + 4 = 0

What are the solutions to the equation x^2-3x=x+1 ?
The solutions to the equation x^2-3x=x+1 are x=2+sqrt(5),x=2-sqrt(5)
Find the zeros of x^2-3x=x+1
The zeros of x^2-3x=x+1 are x=2+sqrt(5),x=2-sqrt(5)