What are the solutions to the equation completesquare 3y^2+12y+12=0 ?

The solutions to the equation completesquare 3y^2+12y+12=0 are y=-2

Find the zeros of completesquare 3y^2+12y+12=0

The zeros of completesquare 3y^2+12y+12=0 are y=-2

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3 y^{2} + 12 y + 12 = 0

y = - 2

Solution steps

3 y^{2} + 12 y + 12 = 0

Move

12

to the right side

3 y^{2} + 12 y = - 12

Divide both sides by

3

\frac{3 y ^{2} + 12 y}{3} = \frac{- 12}{3}

y^{2} + 4 y = - 4

Rewrite in the form

(x + a)^{2} = b

(y + 2)^{2} = 0

Solve

y + 2 = 0 : y = - 2

The solution to the quadratic equation is:

y = - 2

x^{2} + 4 x + 7

6 + x^{2} = 15

- 2 x^{2} + 4 x + 9 = 11

x^{2} + 5 + 4 = 0

3 (p + 1)^{2} = 81

What are the solutions to the equation completesquare 3y^2+12y+12=0 ?
The solutions to the equation completesquare 3y^2+12y+12=0 are y=-2
Find the zeros of completesquare 3y^2+12y+12=0
The zeros of completesquare 3y^2+12y+12=0 are y=-2