What are the solutions to the equation 2(t+8)^2-6=18 ?

The solutions to the equation 2(t+8)^2-6=18 are t=2sqrt(3)-8,t=-2sqrt(3)-8

Find the zeros of 2(t+8)^2-6=18

The zeros of 2(t+8)^2-6=18 are t=2sqrt(3)-8,t=-2sqrt(3)-8

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2 (t + 8)^{2} - 6 = 18

t = 23 - 8, t = - 23 - 8

Decimal Notation

t = - 4.53589 \dots, t = - 11.46410 \dots

Solution steps

2 (t + 8)^{2} - 6 = 18

Move

6

to the right side

2 (t + 8)^{2} = 24

Divide both sides by

2

(t + 8)^{2} = 12

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

t + 8 = 12 : t = 23 - 8

Solve

t + 8 = - 12 : t = - 23 - 8

The solutions to the quadratic equation are:

t = 23 - 8, t = - 23 - 8

10 x^{2} + 21 x - 10

\frac{3}{5} \cdot \frac{5}{3}

x^{2} - 6 x = 40

3 x^{2} - 7 x - 26 = 0

486 + 108 x + 6 x^{2}

What are the solutions to the equation 2(t+8)^2-6=18 ?
The solutions to the equation 2(t+8)^2-6=18 are t=2sqrt(3)-8,t=-2sqrt(3)-8
Find the zeros of 2(t+8)^2-6=18
The zeros of 2(t+8)^2-6=18 are t=2sqrt(3)-8,t=-2sqrt(3)-8