What are the solutions to the equation n^2+10n=-21 ?

The solutions to the equation n^2+10n=-21 are n=-3,n=-7

Find the zeros of n^2+10n=-21

The zeros of n^2+10n=-21 are n=-3,n=-7

Popular >

n^{2} + 10 n = - 21

n = - 3, n = - 7

Solution steps

n^{2} + 10 n = - 21

Move

21

to the left side

n^{2} + 10 n + 21 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 1 \cdot 21}{2 \cdot 1}

1 0^{2} - 4 \cdot 1 \cdot 21 = 4

n_{1, 2} = \frac{- 10 \pm 4}{2 \cdot 1}

Separate the solutions

n_{1} = \frac{- 10 + 4}{2 \cdot 1}, n_{2} = \frac{- 10 - 4}{2 \cdot 1}

n = \frac{- 10 + 4}{2 \cdot 1} : - 3

n = \frac{- 10 - 4}{2 \cdot 1} : - 7

The solutions to the quadratic equation are:

n = - 3, n = - 7

9 b^{2} - 49 = 0

0. 3^{2} + 0. 4^{2} = x^{2}

3 x (x - 3) = 3 - 9 x

t, 0 = 0 + 17.2 \cdot t + \frac{1}{2} (- 9.8) t^{2}

\frac{x ^{2}}{2} + \frac{13 x}{20} = \frac{3}{2}

What are the solutions to the equation n^2+10n=-21 ?
The solutions to the equation n^2+10n=-21 are n=-3,n=-7
Find the zeros of n^2+10n=-21
The zeros of n^2+10n=-21 are n=-3,n=-7