What are the solutions to the equation 3y^2-13y-15=0 ?

The solutions to the equation 3y^2-13y-15=0 are y=(13+sqrt(349))/6 ,y=(13-sqrt(349))/6

Find the zeros of 3y^2-13y-15=0

The zeros of 3y^2-13y-15=0 are y=(13+sqrt(349))/6 ,y=(13-sqrt(349))/6

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3 y^{2} - 13 y - 15 = 0

y = \frac{13 + 349}{6}, y = \frac{13 - 349}{6}

Decimal Notation

y = 5.28025 \dots, y = - 0.94692 \dots

Solution steps

3 y^{2} - 13 y - 15 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 13 ) \pm ( - 13 ) ^{2} - 4 \cdot 3 ( - 15 )}{2 \cdot 3}

(- 13)^{2} - 4 \cdot 3 (- 15) = 349

y_{1, 2} = \frac{- ( - 13 ) \pm 349}{2 \cdot 3}

Separate the solutions

y_{1} = \frac{- ( - 13 ) + 349}{2 \cdot 3}, y_{2} = \frac{- ( - 13 ) - 349}{2 \cdot 3}

y = \frac{- ( - 13 ) + 349}{2 \cdot 3} : \frac{13 + 349}{6}

y = \frac{- ( - 13 ) - 349}{2 \cdot 3} : \frac{13 - 349}{6}

The solutions to the quadratic equation are:

y = \frac{13 + 349}{6}, y = \frac{13 - 349}{6}

5 x^{2} - 5 x + 5 = 0

2 (x - 5)^{2} + 7 = 79

9 x^{2} + 8 x - 13 = 0

- 4 x^{2} - 72 x - 68 = 0

x^{2} - 7 x + 12 = 0

What are the solutions to the equation 3y^2-13y-15=0 ?
The solutions to the equation 3y^2-13y-15=0 are y=(13+sqrt(349))/6 ,y=(13-sqrt(349))/6
Find the zeros of 3y^2-13y-15=0
The zeros of 3y^2-13y-15=0 are y=(13+sqrt(349))/6 ,y=(13-sqrt(349))/6