What are the solutions to the equation (x+4)(x-2)=55 ?

The solutions to the equation (x+4)(x-2)=55 are x=7,x=-9

Find the zeros of (x+4)(x-2)=55

The zeros of (x+4)(x-2)=55 are x=7,x=-9

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x + 4) (x - 2) = 55

x = 7, x = - 9

Solution steps

(x + 4) (x - 2) = 55

Expand

(x + 4) (x - 2) : x^{2} + 2 x - 8

x^{2} + 2 x - 8 = 55

Move

55

to the left side

x^{2} + 2 x - 63 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot ( - 63 )}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot (- 63) = 16

x_{1, 2} = \frac{- 2 \pm 16}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 + 16}{2 \cdot 1}, x_{2} = \frac{- 2 - 16}{2 \cdot 1}

x = \frac{- 2 + 16}{2 \cdot 1} : 7

x = \frac{- 2 - 16}{2 \cdot 1} : - 9

The solutions to the quadratic equation are:

x = 7, x = - 9

2 y^{2} - 7 y + 3 = 0

x, x^{2} - 8 x + 3 = 0

3 x^{2} + 19 x^{2} + 21 x + 5 = 0

- 2 x^{2} - 3 = 5 x^{2} + 25

x^{2} + 5 - 6 = 0

What are the solutions to the equation (x+4)(x-2)=55 ?
The solutions to the equation (x+4)(x-2)=55 are x=7,x=-9
Find the zeros of (x+4)(x-2)=55
The zeros of (x+4)(x-2)=55 are x=7,x=-9