What are the solutions to the equation factor 12x^2-13x-35=0 ?

The solutions to the equation factor 12x^2-13x-35=0 are x=-5/4 ,x= 7/3

Find the zeros of factor 12x^2-13x-35=0

The zeros of factor 12x^2-13x-35=0 are x=-5/4 ,x= 7/3

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12 x^{2} - 13 x - 35 = 0

x = - \frac{5}{4}, x = \frac{7}{3}

Decimal Notation

x = - 1.25, x = 2.33333 \dots

Solution steps

12 x^{2} - 13 x - 35 = 0

Factor

12 x^{2} - 13 x - 35 : (4 x + 5) (3 x - 7)

(4 x + 5) (3 x - 7) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

4 x + 5 = 0 or 3 x - 7 = 0

Solve

4 x + 5 = 0 : x = - \frac{5}{4}

Solve

3 x - 7 = 0 : x = \frac{7}{3}

The solutions to the quadratic equation are:

x = - \frac{5}{4}, x = \frac{7}{3}

b^{2} - 7 b + 12 = 0

6 x^{2} - 15 = 2 x^{2} + 10

2 X^{2} - 12 X = 0

5 x = 4 x^{2} - 2

y, (y + 1)^{2} = (2 - x) ln (x)

What are the solutions to the equation factor 12x^2-13x-35=0 ?
The solutions to the equation factor 12x^2-13x-35=0 are x=-5/4 ,x= 7/3
Find the zeros of factor 12x^2-13x-35=0
The zeros of factor 12x^2-13x-35=0 are x=-5/4 ,x= 7/3