What are the solutions to the equation 2z^2+3z-6=0 ?

The solutions to the equation 2z^2+3z-6=0 are z=(-3+sqrt(57))/4 ,z=(-3-sqrt(57))/4

Find the zeros of 2z^2+3z-6=0

The zeros of 2z^2+3z-6=0 are z=(-3+sqrt(57))/4 ,z=(-3-sqrt(57))/4

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2 z^{2} + 3 z - 6 = 0

z = \frac{- 3 + 57}{4}, z = \frac{- 3 - 57}{4}

Decimal Notation

z = 1.13745 \dots, z = - 2.63745 \dots

Solution steps

2 z^{2} + 3 z - 6 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 2 ( - 6 )}{2 \cdot 2}

3^{2} - 4 \cdot 2 (- 6) = 57

z_{1, 2} = \frac{- 3 \pm 57}{2 \cdot 2}

Separate the solutions

z_{1} = \frac{- 3 + 57}{2 \cdot 2}, z_{2} = \frac{- 3 - 57}{2 \cdot 2}

z = \frac{- 3 + 57}{2 \cdot 2} : \frac{- 3 + 57}{4}

z = \frac{- 3 - 57}{2 \cdot 2} : \frac{- 3 - 57}{4}

The solutions to the quadratic equation are:

z = \frac{- 3 + 57}{4}, z = \frac{- 3 - 57}{4}

3 y^{2} = 0

x^{2} = 1 0^{2} + 1 2^{2}

- 3 x^{2} + 195 x - 650 = 2200

x^{2} + 6 x - 144 = 0

(x + 6) (x - 6) = 13

What are the solutions to the equation 2z^2+3z-6=0 ?
The solutions to the equation 2z^2+3z-6=0 are z=(-3+sqrt(57))/4 ,z=(-3-sqrt(57))/4
Find the zeros of 2z^2+3z-6=0
The zeros of 2z^2+3z-6=0 are z=(-3+sqrt(57))/4 ,z=(-3-sqrt(57))/4