What are the solutions to the equation -3x^2+195x-650=2200 ?

The solutions to the equation -3x^2+195x-650=2200 are x=(5(13-sqrt(17)))/2 ,x=(5(13+sqrt(17)))/2

Find the zeros of -3x^2+195x-650=2200

The zeros of -3x^2+195x-650=2200 are x=(5(13-sqrt(17)))/2 ,x=(5(13+sqrt(17)))/2

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- 3 x^{2} + 195 x - 650 = 2200

x = \frac{5 ( 13 - 17 )}{2}, x = \frac{5 ( 13 + 17 )}{2}

Decimal Notation

x = 22.19223 \dots, x = 42.80776 \dots

Solution steps

- 3 x^{2} + 195 x - 650 = 2200

Move

2200

to the left side

- 3 x^{2} + 195 x - 2850 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 195 \pm 19 5 ^{2} - 4 ( - 3 ) ( - 2850 )}{2 ( - 3 )}

19 5^{2} - 4 (- 3) (- 2850) = 1517

x_{1, 2} = \frac{- 195 \pm 15 17}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- 195 + 15 17}{2 ( - 3 )}, x_{2} = \frac{- 195 - 15 17}{2 ( - 3 )}

x = \frac{- 195 + 15 17}{2 ( - 3 )} : \frac{5 ( 13 - 17 )}{2}

x = \frac{- 195 - 15 17}{2 ( - 3 )} : \frac{5 ( 13 + 17 )}{2}

The solutions to the quadratic equation are:

x = \frac{5 ( 13 - 17 )}{2}, x = \frac{5 ( 13 + 17 )}{2}

x^{2} + 6 x - 144 = 0

(x + 6) (x - 6) = 13

x^{2} + 6 x = 24

56 = - 16 t^{2} + 60 t

(2 x - 5) (x - 3) = 0

What are the solutions to the equation -3x^2+195x-650=2200 ?
The solutions to the equation -3x^2+195x-650=2200 are x=(5(13-sqrt(17)))/2 ,x=(5(13+sqrt(17)))/2
Find the zeros of -3x^2+195x-650=2200
The zeros of -3x^2+195x-650=2200 are x=(5(13-sqrt(17)))/2 ,x=(5(13+sqrt(17)))/2