What are the solutions to the equation x^2=10^2+12^2 ?

The solutions to the equation x^2=10^2+12^2 are x=2sqrt(61),x=-2sqrt(61)

Find the zeros of x^2=10^2+12^2

The zeros of x^2=10^2+12^2 are x=2sqrt(61),x=-2sqrt(61)

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x^{2} = 1 0^{2} + 1 2^{2}

x = 261, x = - 261

Decimal Notation

x = 15.62049 \dots, x = - 15.62049 \dots

Solution steps

x^{2} = 1 0^{2} + 1 2^{2}

Simplify

1 0^{2} + 1 2^{2} : 244

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 244, x = - 244

244 = 261

- 244 = - 261

x = 261, x = - 261

- 3 x^{2} + 195 x - 650 = 2200

x^{2} + 6 x - 144 = 0

(x + 6) (x - 6) = 13

x^{2} + 6 x = 24

56 = - 16 t^{2} + 60 t

What are the solutions to the equation x^2=10^2+12^2 ?
The solutions to the equation x^2=10^2+12^2 are x=2sqrt(61),x=-2sqrt(61)
Find the zeros of x^2=10^2+12^2
The zeros of x^2=10^2+12^2 are x=2sqrt(61),x=-2sqrt(61)