What are the solutions to the equation x^2+6x=24 ?

The solutions to the equation x^2+6x=24 are x=-3+sqrt(33),x=-3-sqrt(33)

Find the zeros of x^2+6x=24

The zeros of x^2+6x=24 are x=-3+sqrt(33),x=-3-sqrt(33)

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x^{2} + 6 x = 24

x = - 3 + 33, x = - 3 - 33

Decimal Notation

x = 2.74456 \dots, x = - 8.74456 \dots

Solution steps

x^{2} + 6 x = 24

Move

24

to the left side

x^{2} + 6 x - 24 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot ( - 24 )}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot (- 24) = 233

x_{1, 2} = \frac{- 6 \pm 2 33}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 6 + 2 33}{2 \cdot 1}, x_{2} = \frac{- 6 - 2 33}{2 \cdot 1}

x = \frac{- 6 + 2 33}{2 \cdot 1} : - 3 + 33

x = \frac{- 6 - 2 33}{2 \cdot 1} : - 3 - 33

The solutions to the quadratic equation are:

x = - 3 + 33, x = - 3 - 33

56 = - 16 t^{2} + 60 t

(2 x - 5) (x - 3) = 0

c^{2} = 16 + 25

0.25 = (\frac{( b - 1 )}{6})^{2}

20 + 12 v^{2} - 40 = - 10 v^{2} + 80 + 18 v^{2}

What are the solutions to the equation x^2+6x=24 ?
The solutions to the equation x^2+6x=24 are x=-3+sqrt(33),x=-3-sqrt(33)
Find the zeros of x^2+6x=24
The zeros of x^2+6x=24 are x=-3+sqrt(33),x=-3-sqrt(33)