What are the solutions to the equation 56=-16t^2+60t ?

The solutions to the equation 56=-16t^2+60t are t= 7/4 ,t=2

Find the zeros of 56=-16t^2+60t

The zeros of 56=-16t^2+60t are t= 7/4 ,t=2

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56 = - 16 t^{2} + 60 t

t = \frac{7}{4}, t = 2

Decimal Notation

t = 1.75, t = 2

Solution steps

56 = - 16 t^{2} + 60 t

Switch sides

- 16 t^{2} + 60 t = 56

Move

56

to the left side

- 16 t^{2} + 60 t - 56 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 60 \pm 6 0 ^{2} - 4 ( - 16 ) ( - 56 )}{2 ( - 16 )}

6 0^{2} - 4 (- 16) (- 56) = 4

t_{1, 2} = \frac{- 60 \pm 4}{2 ( - 16 )}

Separate the solutions

t_{1} = \frac{- 60 + 4}{2 ( - 16 )}, t_{2} = \frac{- 60 - 4}{2 ( - 16 )}

t = \frac{- 60 + 4}{2 ( - 16 )} : \frac{7}{4}

t = \frac{- 60 - 4}{2 ( - 16 )} : 2

The solutions to the quadratic equation are:

t = \frac{7}{4}, t = 2

(2 x - 5) (x - 3) = 0

c^{2} = 16 + 25

0.25 = (\frac{( b - 1 )}{6})^{2}

20 + 12 v^{2} - 40 = - 10 v^{2} + 80 + 18 v^{2}

x^{2} + 8 x - 7 = 77

What are the solutions to the equation 56=-16t^2+60t ?
The solutions to the equation 56=-16t^2+60t are t= 7/4 ,t=2
Find the zeros of 56=-16t^2+60t
The zeros of 56=-16t^2+60t are t= 7/4 ,t=2