What are the solutions to the equation c^2=16+25 ?

The solutions to the equation c^2=16+25 are c=sqrt(41),c=-sqrt(41)

Find the zeros of c^2=16+25

The zeros of c^2=16+25 are c=sqrt(41),c=-sqrt(41)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

c^{2} = 16 + 25

c = 41, c = - 41

Decimal Notation

c = 6.40312 \dots, c = - 6.40312 \dots

Solution steps

c^{2} = 16 + 25

Add the numbers:

16 + 25 = 41

c^{2} = 41

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

c = 41, c = - 41

0.25 = (\frac{( b - 1 )}{6})^{2}

20 + 12 v^{2} - 40 = - 10 v^{2} + 80 + 18 v^{2}

x^{2} + 8 x - 7 = 77

2 x^{2} + 8 x = - 32

2 x^{2} + 3 x - 560 = 0

What are the solutions to the equation c^2=16+25 ?
The solutions to the equation c^2=16+25 are c=sqrt(41),c=-sqrt(41)
Find the zeros of c^2=16+25
The zeros of c^2=16+25 are c=sqrt(41),c=-sqrt(41)