What are the solutions to the equation 20+12v^2-40=-10v^2+80+18v^2 ?

The solutions to the equation 20+12v^2-40=-10v^2+80+18v^2 are v=5,v=-5

Find the zeros of 20+12v^2-40=-10v^2+80+18v^2

The zeros of 20+12v^2-40=-10v^2+80+18v^2 are v=5,v=-5

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20 + 12 v^{2} - 40 = - 10 v^{2} + 80 + 18 v^{2}

v = 5, v = - 5

Solution steps

20 + 12 v^{2} - 40 = - 10 v^{2} + 80 + 18 v^{2}

Move

20

to the right side

12 v^{2} - 40 = 8 v^{2} + 60

Move

40

to the right side

12 v^{2} = 8 v^{2} + 100

Move

8 v^{2}

to the left side

4 v^{2} = 100

Divide both sides by

4

v^{2} = 25

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

v = 25, v = - 25

25 = 5

- 25 = - 5

v = 5, v = - 5

x^{2} + 8 x - 7 = 77

2 x^{2} + 8 x = - 32

2 x^{2} + 3 x - 560 = 0

x^{2} - 3 x - 2 = - 4

x^{2} + 10 x - 1 = 0

What are the solutions to the equation 20+12v^2-40=-10v^2+80+18v^2 ?
The solutions to the equation 20+12v^2-40=-10v^2+80+18v^2 are v=5,v=-5
Find the zeros of 20+12v^2-40=-10v^2+80+18v^2
The zeros of 20+12v^2-40=-10v^2+80+18v^2 are v=5,v=-5