What are the solutions to the equation 2x^2+3x-560=0 ?

The solutions to the equation 2x^2+3x-560=0 are x=16,x=-35/2

Find the zeros of 2x^2+3x-560=0

The zeros of 2x^2+3x-560=0 are x=16,x=-35/2

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2 x^{2} + 3 x - 560 = 0

x = 16, x = - \frac{35}{2}

Decimal Notation

x = 16, x = - 17.5

Solution steps

2 x^{2} + 3 x - 560 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 2 ( - 560 )}{2 \cdot 2}

3^{2} - 4 \cdot 2 (- 560) = 67

x_{1, 2} = \frac{- 3 \pm 67}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 3 + 67}{2 \cdot 2}, x_{2} = \frac{- 3 - 67}{2 \cdot 2}

x = \frac{- 3 + 67}{2 \cdot 2} : 16

x = \frac{- 3 - 67}{2 \cdot 2} : - \frac{35}{2}

The solutions to the quadratic equation are:

x = 16, x = - \frac{35}{2}

x^{2} - 3 x - 2 = - 4

x^{2} + 10 x - 1 = 0

2 (x + 1)^{2} + 7 = 1

m^{2} + 4 m + 8 = 0

x, (2 x + j^{3} y)^{2} - 6 - j^{12} = 0

What are the solutions to the equation 2x^2+3x-560=0 ?
The solutions to the equation 2x^2+3x-560=0 are x=16,x=-35/2
Find the zeros of 2x^2+3x-560=0
The zeros of 2x^2+3x-560=0 are x=16,x=-35/2