What are the solutions to the equation x^2-3x-2=-4 ?

The solutions to the equation x^2-3x-2=-4 are x=2,x=1

Find the zeros of x^2-3x-2=-4

The zeros of x^2-3x-2=-4 are x=2,x=1

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x^{2} - 3 x - 2 = - 4

x = 2, x = 1

Solution steps

x^{2} - 3 x - 2 = - 4

Move

4

to the left side

x^{2} - 3 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 1 \cdot 2}{2 \cdot 1}

(- 3)^{2} - 4 \cdot 1 \cdot 2 = 1

x_{1, 2} = \frac{- ( - 3 ) \pm 1}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 1}{2 \cdot 1}, x_{2} = \frac{- ( - 3 ) - 1}{2 \cdot 1}

x = \frac{- ( - 3 ) + 1}{2 \cdot 1} : 2

x = \frac{- ( - 3 ) - 1}{2 \cdot 1} : 1

The solutions to the quadratic equation are:

x = 2, x = 1

x^{2} + 10 x - 1 = 0

2 (x + 1)^{2} + 7 = 1

m^{2} + 4 m + 8 = 0

x, (2 x + j^{3} y)^{2} - 6 - j^{12} = 0

0 = x^{2} - 2 x + 6

What are the solutions to the equation x^2-3x-2=-4 ?
The solutions to the equation x^2-3x-2=-4 are x=2,x=1
Find the zeros of x^2-3x-2=-4
The zeros of x^2-3x-2=-4 are x=2,x=1