What are the solutions to the equation quadraticformula 2x^2+3x-5=0 ?

The solutions to the equation quadraticformula 2x^2+3x-5=0 are x=1,x=-5/2

Find the zeros of quadraticformula 2x^2+3x-5=0

The zeros of quadraticformula 2x^2+3x-5=0 are x=1,x=-5/2

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2 x^{2} + 3 x - 5 = 0

x = 1, x = - \frac{5}{2}

Decimal Notation

x = 1, x = - 2.5

Solution steps

2 x^{2} + 3 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 2 ( - 5 )}{2 \cdot 2}

3^{2} - 4 \cdot 2 (- 5) = 7

x_{1, 2} = \frac{- 3 \pm 7}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 3 + 7}{2 \cdot 2}, x_{2} = \frac{- 3 - 7}{2 \cdot 2}

x = \frac{- 3 + 7}{2 \cdot 2} : 1

x = \frac{- 3 - 7}{2 \cdot 2} : - \frac{5}{2}

The solutions to the quadratic equation are:

x = 1, x = - \frac{5}{2}

m^{2} + 96 m + \frac{8}{3} = 0

8 x^{2} = 4

80 = 80 t - 16 t^{2}

(22 + 3) x^{2} - (22 + 4) x + 2 = 0

x^{2} - 3 x - 24 = 0

What are the solutions to the equation quadraticformula 2x^2+3x-5=0 ?
The solutions to the equation quadraticformula 2x^2+3x-5=0 are x=1,x=-5/2
Find the zeros of quadraticformula 2x^2+3x-5=0
The zeros of quadraticformula 2x^2+3x-5=0 are x=1,x=-5/2