What are the solutions to the equation 3x^2+9x-1=-3x^2 ?

The solutions to the equation 3x^2+9x-1=-3x^2 are x=(-9+sqrt(105))/(12),x=(-9-sqrt(105))/(12)

Find the zeros of 3x^2+9x-1=-3x^2

The zeros of 3x^2+9x-1=-3x^2 are x=(-9+sqrt(105))/(12),x=(-9-sqrt(105))/(12)

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3 x^{2} + 9 x - 1 = - 3 x^{2}

x = \frac{- 9 + 105}{12}, x = \frac{- 9 - 105}{12}

Decimal Notation

x = 0.10391 \dots, x = - 1.60391 \dots

Solution steps

3 x^{2} + 9 x - 1 = - 3 x^{2}

Move

3 x^{2}

to the left side

6 x^{2} + 9 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 6 ( - 1 )}{2 \cdot 6}

9^{2} - 4 \cdot 6 (- 1) = 105

x_{1, 2} = \frac{- 9 \pm 105}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 9 + 105}{2 \cdot 6}, x_{2} = \frac{- 9 - 105}{2 \cdot 6}

x = \frac{- 9 + 105}{2 \cdot 6} : \frac{- 9 + 105}{12}

x = \frac{- 9 - 105}{2 \cdot 6} : \frac{- 9 - 105}{12}

The solutions to the quadratic equation are:

x = \frac{- 9 + 105}{12}, x = \frac{- 9 - 105}{12}

x^{2} + 3 x = - 10

6 x^{2} - 6 x - 120 = 0

- x^{2} + 3 x + 6 = 0

z = z^{2}

18 x^{2} + 2 x + 6 = 0

What are the solutions to the equation 3x^2+9x-1=-3x^2 ?
The solutions to the equation 3x^2+9x-1=-3x^2 are x=(-9+sqrt(105))/(12),x=(-9-sqrt(105))/(12)
Find the zeros of 3x^2+9x-1=-3x^2
The zeros of 3x^2+9x-1=-3x^2 are x=(-9+sqrt(105))/(12),x=(-9-sqrt(105))/(12)