What are the solutions to the equation z=z^2 ?

The solutions to the equation z=z^2 are z=1,z=0

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z=z^2

z = z^{2}

z = 1, z = 0

Solution steps

z = z^{2}

Switch sides

z^{2} = z

Move

z

to the left side

z^{2} - z = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot 0 = 1

z_{1, 2} = \frac{- ( - 1 ) \pm 1}{2 \cdot 1}

Separate the solutions

z_{1} = \frac{- ( - 1 ) + 1}{2 \cdot 1}, z_{2} = \frac{- ( - 1 ) - 1}{2 \cdot 1}

z = \frac{- ( - 1 ) + 1}{2 \cdot 1} : 1

z = \frac{- ( - 1 ) - 1}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

z = 1, z = 0

18 x^{2} + 2 x + 6 = 0

s^{2} + 2 \cdot s + 2 = 0

a^{2} + 5 = 7

y, x (x - y) + y (y - z) + z (z - x) = 1

- 3 x^{2} - 9 x = 0

What are the solutions to the equation z=z^2 ?
The solutions to the equation z=z^2 are z=1,z=0
Find the zeros of z=z^2
The zeros of z=z^2 are z=1,z=0