What are the solutions to the equation 18x^2+2x+6=0 ?

The solutions to the equation 18x^2+2x+6=0 are x=-1/18+i(sqrt(107))/(18),x=-1/18-i(sqrt(107))/(18)

Find the zeros of 18x^2+2x+6=0

The zeros of 18x^2+2x+6=0 are x=-1/18+i(sqrt(107))/(18),x=-1/18-i(sqrt(107))/(18)

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18 x^{2} + 2 x + 6 = 0

x = - \frac{1}{18} + i \frac{107}{18}, x = - \frac{1}{18} - i \frac{107}{18}

Solution steps

18 x^{2} + 2 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 18 \cdot 6}{2 \cdot 18}

Simplify

2^{2} - 4 \cdot 18 \cdot 6 : 2107 i

x_{1, 2} = \frac{- 2 \pm 2 107 i}{2 \cdot 18}

Separate the solutions

x_{1} = \frac{- 2 + 2 107 i}{2 \cdot 18}, x_{2} = \frac{- 2 - 2 107 i}{2 \cdot 18}

x = \frac{- 2 + 2 107 i}{2 \cdot 18} : - \frac{1}{18} + i \frac{107}{18}

x = \frac{- 2 - 2 107 i}{2 \cdot 18} : - \frac{1}{18} - i \frac{107}{18}

The solutions to the quadratic equation are:

x = - \frac{1}{18} + i \frac{107}{18}, x = - \frac{1}{18} - i \frac{107}{18}

s^{2} + 2 \cdot s + 2 = 0

a^{2} + 5 = 7

y, x (x - y) + y (y - z) + z (z - x) = 1

- 3 x^{2} - 9 x = 0

4 x^{2} + 3 x = 0

What are the solutions to the equation 18x^2+2x+6=0 ?
The solutions to the equation 18x^2+2x+6=0 are x=-1/18+i(sqrt(107))/(18),x=-1/18-i(sqrt(107))/(18)
Find the zeros of 18x^2+2x+6=0
The zeros of 18x^2+2x+6=0 are x=-1/18+i(sqrt(107))/(18),x=-1/18-i(sqrt(107))/(18)