What are the solutions to the equation s^2+2*s+2=0 ?

The solutions to the equation s^2+2*s+2=0 are s=-1+i,s=-1-i

Find the zeros of s^2+2*s+2=0

The zeros of s^2+2*s+2=0 are s=-1+i,s=-1-i

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s^{2} + 2 \cdot s + 2 = 0

s = - 1 + i, s = - 1 - i

Solution steps

s^{2} + 2 s + 2 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot 2}{2 \cdot 1}

Simplify

2^{2} - 4 \cdot 1 \cdot 2 : 2 i

s_{1, 2} = \frac{- 2 \pm 2 i}{2 \cdot 1}

Separate the solutions

s_{1} = \frac{- 2 + 2 i}{2 \cdot 1}, s_{2} = \frac{- 2 - 2 i}{2 \cdot 1}

s = \frac{- 2 + 2 i}{2 \cdot 1} : - 1 + i

s = \frac{- 2 - 2 i}{2 \cdot 1} : - 1 - i

The solutions to the quadratic equation are:

s = - 1 + i, s = - 1 - i

a^{2} + 5 = 7

y, x (x - y) + y (y - z) + z (z - x) = 1

- 3 x^{2} - 9 x = 0

4 x^{2} + 3 x = 0

4 m^{2} + 8 m + 3 = 0

What are the solutions to the equation s^2+2*s+2=0 ?
The solutions to the equation s^2+2*s+2=0 are s=-1+i,s=-1-i
Find the zeros of s^2+2*s+2=0
The zeros of s^2+2*s+2=0 are s=-1+i,s=-1-i